LiveCode Forums.

I did not manage to upload files to my database. Does anyone have any idea. What happens is that the database responds "Unsupported media type" It is a common SQL database, so it should not be that tricky.

This is the html form:

<form action="api/upload" method="POST" enctype="multipart/form-data">
<input type="text" name="k" value="88C9607F-4A89-447D-97C4-BC124DDA7DBF” />

</form>

And this is what I try to do:

local tData,tPic

constant gUid = "88C9607F-4A89-447D-97C4-BC124DDA7DBF" -- just for test

on mouseUp
      set the vis of the templateImage to false
      mobilePickPhoto "library"
      put the last image into tPic
   put buildIt() into tData
   post tData to URL myUrl
   answer it-- just for test
   set the httpHeaders to empty
end mouseUp

function buildIt
 put "Content-Disposition: form-data; name=" & K & crlf after tData
put "Content-Disposition: form-data; value=" & gUid & crlf after tData
   put tPic & crlf after tData
   put "Content-Type: multipart/form-data; boundary=" into theHeader
   set the httpHeaders to theHeader
   return tData
end buildIt


What am I doing wrong?


/// Peter

Hi Peter,

quick guess: Do K and gUID not need to be on QUOTES?
...
put "Content-Disposition: form-data; name=" & QUOTE & K & QUOTE & crlf after tData
put "Content-Disposition: form-data; value=" & QUOTE & gUid & QUOTE & crlf after tData
...
?


Best

Klaus

Hi Klaus,

I've tried it, but it did not work so I removed them.
The only difference is that the database responds "One or more error occurred" or "Unsupported media type"

I'm stuck!

///Peter