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Duplicating a card?

Posted: Thu Jul 05, 2007 6:25 pm
by derek
I have a card in my stack, and I want to duplicate it. Usually, the duplicate will serve as the next card in the same stack. Sometimes, I will want to place it in a different sub stack or another main stack.

These online forums find no messages when I search for "duplicate card." The same is true for the User Guide. Under "Duplicate" in the User Guide, there is a mention of using Edit>Duplicate from the Revolution menus. However, when I select a card, Cut, Copy, Duplicate and Replicate are all greyed out, and unavailable.

What am I doing wrong? How can I duplicate a card within a stack or between stacks?

Thanks,
Derek

Posted: Thu Jul 05, 2007 6:51 pm
by Klaus
Hi Derek,

you are looking for "clone" and "copy"! :-)

...
clone this cd
## In the same stack

...
copy cd "My card" of stack "A" to stack "B"
## Between stacks

Hope that helps.


Best

Klaus Major

Posted: Thu Jul 05, 2007 9:49 pm
by derek
Thank you, Klaus. This will solve my problem. It's great to have such quick answers from the forum. I hope someday the documentation will improve enough that simple questions like this will be findable.

Derek

Re: Duplicating a card?

Posted: Tue Nov 12, 2013 4:37 am
by marksmithhfx
And Derek, thanks for asking the question. I had the same question myself but this time I was able to come here and find the answer :D Actually I did not even have to search here, Google found it for me. Its worth asking in Google, sometimes it will point you in the right direction.

Cheers,

Mark

Re:

Posted: Tue Nov 12, 2013 5:13 am
by FourthWorld
derek wrote:Thank you, Klaus. This will solve my problem. It's great to have such quick answers from the forum. I hope someday the documentation will improve enough that simple questions like this will be findable.
The key will be to add a good index, so to help that along could you tell us what you looked for in the docs? Knowing how folks conceptualize LC when learning will make a big difference in coming up with a useful index. Thanks in advance.