put name of button into

[DavJans]

in the dictionary I found this

put me into myVariable -- puts contents, if me is a container
put me into myVariable -- puts name, if me is not a container

however..

on mouseUp
put me into fld "Test" on card "card2"
go to card "card2"
end mouseUp

... does not work.

Is it counting a button as a container or is a button not considered either? is there a way to do this?

[Klaus]

Hi DavJans,

ME will not return the name of an object, you need to:
...
put the short name of me into fld "xyz" OF cd "abc"
## -> xyz
...
## Or:
put the name of me into fld "xyz" OF cd "abc"
## Will also return the TYPE of the object -> button "xyz"
...


Best

Klaus

[DavJans]

Thank you Klaus

[dunbarx]

Hi.

A button is indeed a container:

Code: Select all

on mouseUp
   put "xxx" into btn 1
   answer btn 1
   answer me
end mouseUp

The contents are returned. Twice. But as Klaus said, when referring to "me" in the sense of an object descriptor, and this can be confusing, the syntax changes:

Code: Select all

on mouseUp
   put "xxx" into btn 3
   answer the width of me
end mouseUp

You get, perhaps, 82. Note that the use of "me" here, as in Klaus' example, is usually associated syntactically with a property. Takes practice. So start practicing.

Craig